0分。，，，蒟蒻求dalao捞

dlklwdc @ 2022-08-21 09:23:14

#include <bits/stdc++.h>

using namespace std;
int a1,a2,b1,b2,c1,c2;
double a;
int jisuan(int a,int aa,int b,int bb){//sqrt[(b-a)*(b-a)+(bb-aa)*(bb-aa)]
    double q=abs(sqrt(abs((b-a)*(b-a))+abs((bb-aa)*(bb-aa))));
    return q;
}
int main()
{
    freopen("P5735.in","r",stdin);
    freopen("P5735.out","w",stdout);
    cin>>a1>>a2;
    cin>>b1>>b2;
    cin>>c1>>c2;
    a=abs(jisuan(a1,a2,b1,b2))+abs(jisuan(a1,a2,c1,c2))+abs(jisuan(b1,b2,c1,c2));
    printf("%0.2lf",a);
    fclose(stdin);
    fclose(stdout);
}

by _Haoomff_ @ 2022-08-21 09:24:31

freopen……

by dlklwdc @ 2022-08-21 09:28:32

。。。。。我忘了。。。。。 我是个sb

by dlklwdc @ 2022-08-21 09:30:43

可还是0分。。。

by Chenyichen0420 @ 2022-08-21 10:03:38

int jisuan(...),return 的一定是int型，而你想要的是double型

by Chenyichen0420 @ 2022-08-21 10:08:27

应该是AC代码：

#include<iostream>
#include<algorithm> //万能头文件OK
using namespace std;
int a1, a2, b1, b2, c1, c2; double ans;
double jisuan(int x1, int x2, int y1, int y2) {
    double q = sqrt((x2 - x1)*(x2 - x1) + (y2 - y1)*(y2 - y1));
    return q;
}
int main(){
    cin >> a1 >> a2;
    cin >> b1 >> b2;
    cin >> c1 >> c2;
    ans = jisuan(a1, a2, b1, b2) + jisuan(a1, a2, c1, c2) + jisuan(b1, b2, c1, c2);
    printf("%.2lf", ans);
    return 0;
}

by Chenyichen0420 @ 2022-08-21 10:09:58

不好意思，少一个cmath头文件

by Chenyichen0420 @ 2022-08-21 10:17:57

更正：

#include<iostream>
#include<cmath>
using namespace std;
int main(){
    double x1, y1, x2, y2, x3, y3, ans;
    cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3;
    ans = sqrt((x1 - x2)*(x1 - x2) + (y1 - y2)*(y1 - y2)) + sqrt((x2 - x3)*(x2 - x3) + (y2 - y3)*(y2 - y3)) + sqrt((x1 - x3)*(x1 - x3) + (y1 - y3)*(y1 - y3));
    printf("%.2lf\n", ans);
    return 0;
}

x,y值也应该为double型。

by dlklwdc @ 2022-08-29 22:10:55

谢谢带佬！