C初学者，80分求助，错误点4,7

HJRBill @ 2022-09-09 17:33:58

#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
int main()
{
    char arr[14];
    scanf("%s", arr);
    int one = (arr[0] - '0') * 1;
    int two = (arr[2] - '0') * 2;
    int three = (arr[3] - '0') * 3;
    int four = (arr[4] - '0') * 4;
    int five = (arr[6] - '0') * 5;
    int six = (arr[7] - '0') * 6;
    int seven = (arr[8] - '0') * 7;
    int eight = (arr[9] - '0') * 8;
    int nine = (arr[10] - '0') * 9;
    int ten = arr[12] - '0';
    int number = (one + two + three + four + five + six + seven + eight + nine) % 11;
    if (ten == number)
    {
        printf("Right");
    }
    else if (number == 10 && ten != number)
    {
        arr[12] = 'X';
        printf("%s", arr);
    }
    else
    {
        arr[12] = number + '0';
        printf("%s", arr);
    }
    return 0;
}

by VectorLi @ 2022-09-09 17:53:01

@HJRBill 您没有考虑 arr[12] 为 \texttt{X} 的情况

by _Hu_Tao @ 2022-09-09 17:53:28

细节问题

因为number有可能大于10

首先

number == 10

改为

number >= 10

还有万一number>=10并且ten=='X'呢？

所以完整判断：

else if(number>=10){
        if((number>=10)&&ten=='X'){
            cout<<"Right";
            return 0;
        }else{
            arr[12] = 'X';
            printf("%s", arr);
            return 0;   
        }

by _Hu_Tao @ 2022-09-09 17:54:08

@HJRBill 求关注QAQ

by zhang_kevin @ 2022-09-09 17:59:13

@_Hu_Tao 帮助别人是为了得到关注？

by _Hu_Tao @ 2022-09-09 18:04:38

@zhang_kevin 是求关注，没有强迫

by HJRBill @ 2022-09-09 20:27:56

@VecTest 谢谢大佬指点

by HJRBill @ 2022-09-09 20:36:02

@_Hu_Tao 谢谢大佬，关注了，我确实忽略了arr[12]='X',不过number不能大于10哦，因为我前面使用了%11 所以其实这么改就行了，多谢大佬指点

else if (number >= 10) 
{
   if (ten + '0' == 'X') 
   {
     printf("Right"); 
   } 
   else 
   { 
     arr[12] = 'X'; 
     printf("%s", arr); 
   }
}