lolaFENG @ 2022-09-21 21:19:45
k = int(input())
def sn(x):
sum = 0
for i in range (1, x + 1):
a = 1 / i
i = i + 1
sum = sum + a
return sum
n = 1
while 0 == 0:
if sn(n) > k:
print(n)
break
else:
n = n +1
by Ew_Cors @ 2022-09-21 21:22:16
很暴力。
by LeTu_Jun @ 2022-09-21 21:28:09
很暴力。
by Alvin20100228 @ 2022-09-21 21:37:56
很暴力。
by xwh_Marvelous @ 2022-09-21 21:42:18
再次证明py垃圾
by lolaFENG @ 2022-09-28 14:51:02
LOL好滴~~~
by Wcx20120226 @ 2022-10-06 16:39:20
Yes,it is.