hyhyh @ 2022-09-30 12:50:38
#include <bits/stdc++.h>
using namespace std;
int main()
{
int d=1,
a=0,
b=1,
c=0,
e;
cin>>a;
for(int i=1; i<=a; i=i+1)
{
d=i*d;
c=c+d;
}
cout<<c;
return 0;
}
by liangbowen @ 2022-09-30 12:52:38
@huyaoyang 请使用高精度/python,即一些高级的算法。
话说您是眼瞎吗?
对于
100 \% 的数据,1 \le n \le 50 。注,《深入浅出基础篇》中使用本题作为例题,但是其数据范围只有
n \le 20 ,使用书中的代码无法通过本题。如果希望通过本题,请继续学习第八章高精度的知识。
by cute_overmind @ 2022-09-30 14:35:34
#include<iostream>
using namespace std;
string a[60]={"0","1","3","9","33","153","873","5913","46233","409113","4037913","43954713","522956313","6749977113","93928268313","1401602636313","22324392524313","378011820620313","6780385526348313","128425485935180313","2561327494111820313","53652269665821260313","1177652997443428940313","27029669736328405580313","647478071469567844940313","16158688114800553828940313","419450149241406189412940313","11308319599659758350180940313","316196664211373618851684940313","9157958657951075573395300940313","274410818470142134209703780940313","8497249472648064951935266660940313","271628086406341595119153278820940313","8954945705218228090637347680100940313","304187744744822368938255957323620940313","10637335711130967298604907294846820940313","382630662501032184766604355445682020940313","14146383753727377231082583937026584420940313","537169001220328488991089808037100875620940313","20935051082417771847631371547939998232420940313","836850334330315506193242641144055892504420940313","34289376947494122614363304694584807557656420940313","1439295494700374021157505910939096377494040420940313","61854558558074209658512637979453093884758552420940313","2720126133346522977702138448994068984204397080420940313","122342346998826717539665299944651784048588130840420940313","5624964506810915667389970728744906677010239883800420940313","264248206017979096310354325882356886646207872272920420940313","12678163798554051767172643373255731925167694226950680420940313","620960027832821612639424806694551108812720525606160920420940313","31035053229546199656252032972759319953190362094566672920420940313"};
int main()
{
int n;
cin >> n;
cout << a[n];
}
by hyhyh @ 2022-09-30 15:54:51
这位大佬真肝啊
by ResonCaolol @ 2022-09-30 15:58:31
@huyaoyang
#include<iostream>
#include<cstdio>
using namespace std;
const int maxn=10000;
int main()
{
int n,k,i,j,t;
while(cin>>n){
int a[maxn]={},sum[maxn]={};
sum[0]=0;
k=1,t=1;
for(int e=1;e<=n;e++){
a[0]=1;
for(i=1;i<=e;i++){
for(j=0;j<k;j++){
a[j]=a[j]*i;
}
for(j=0;j<k;j++){
if(a[j]>=10){
a[j+1]+=a[j]/10;
a[j]=a[j]%10;
if(j==k-1) k++;
}
}
}
for(int p=0;p<k;p++){
sum[p]=sum[p]+a[p];
}
for(int p=0;p<t;p++){
if(sum[p+1]>=10){
t++;
}
if(sum[p]>=10){
sum[p+1]+=sum[p]/10;
sum[p]=sum[p]%10;
}
}
for(int q=1;q<k;q++){
a[q]=0;
}
}
for(i=k-1;i>=0;i--){
cout<<sum[i]<<"";
}
cout<<endl;
}
return 0;
}
by hyhyh @ 2022-09-30 16:01:56
@crc666 @Pikacu @liangbowen
谢了
by cute_overmind @ 2022-09-30 18:49:02
@huyaoyang 其实不是我肝, 用Python就能够打表