30分求助！ 大佬们帮忙看看

Dreams_Knight @ 2022-10-09 22:49:09

#include<bits/stdc++.h>
using namespace std;
int a[26];
int main(){
    string s;
    cin >> s;
    int len = s.size();
    for(int i = 0;i < len;i++){
        a[s[i] - 'a']++;
    }
    for(int i = 0;i < len;i++){
        if(a[s[i] - 'a'] == 1){
            cout << s[i];
            return 0;
        }
        else{
            cout << "no";
            return 0;
        }
    }
    return 0;
} 

by Time_Limit_Exceed @ 2022-10-09 23:10:21

@Dreams_Promise 判断完不能直接返回丶

by RE_Automation @ 2022-10-09 23:10:30

题意理解出错

第二个for循环的else应该扔到循环外

否则就是判断字符串的第一位是否只出现一次了

by RE_Automation @ 2022-10-09 23:12:07

#include<bits/stdc++.h>
using namespace std;
int a[26];
int main(){
    string s;
    cin >> s;
    int len = s.size();
    for(int i = 0;i < len;i++){
        a[s[i] - 'a']++;
    }
    for(int i = 0;i < len;i++){
        if(a[s[i] - 'a'] == 1){
            cout << s[i];
            return 0;
        }
    }
    cout<<"no"<<endl;
    return 0;
} 

by RE_Automation @ 2022-10-09 23:12:32

这样就ok了

by Dreams_Knight @ 2022-10-10 22:51:43

谢谢各位大佬