cxkssss678 @ 2022-10-23 14:40:30
ide里第一次循环不进行输入操作，但是进行了输出操作，想循环三次，每次输入一个字符串，但在ide里必须写成4次循环。 这是为啥？？？？
by Troilus @ 2022-10-23 14:50:45
代码呢？
by Resolute_Faith @ 2022-10-23 15:00:51
你也很奇怪
by _SkyDream_ @ 2022-10-23 17:14:48
你写错了
by _SkyDream_ @ 2022-10-23 17:17:11
我觉得你写成了(i=1;i<3;i++)
by cxkssss678 @ 2022-10-24 09:20:33
#include<stdio.h>
#include<string.h>
void doo(int x, int y, char c)
{
int s = 0;
int count = 2;
if (x <= 0)count++;
if (y <= 0)count++;
switch (c)
{
case 'a':
s = x + y;
printf("%d+%d=%d\n", x, y, s);
if (s <= 0) count++;
while (x != 0)
{
count++;
x = x / 10;
}
while (y != 0)
{
count++;
y = y / 10;
}
while (s != 0)
{
count++;
s = s / 10;
}
printf("%d", count);
break;
case 'b':
s = x - y;
printf("%d-%d=%d\n", x, y, s);
if (s <= 0) count++;
while (x != 0)
{
count++;
x = x / 10;
}
while (y != 0)
{
count++;
y = y / 10;
}
while (s != 0)
{
count++;
s = s / 10;
}
printf("%d", count);
break;
case 'c':
s = x * y;
printf("%d*%d=%d\n", x, y, s);
if (s <= 0) count++;
while (x != 0)
{
count++;
x = x / 10;
}
while (y != 0)
{
count++;
y = y / 10;
}
while (s != 0)
{
count++;
s = s / 10;
}
printf("%d", count);
}
}
int main()
{
int n;
scanf("%d", &n);
getchar();
int x, y;
char c='!';
char S[100] = { 0 };
for (int i = 0; i <= n; i++)
{
memset(S, 0, sizeof(S));
gets(S);
if (S[0] == 'a' || S[0] == 'b' || S[0] == 'c')
{
c = S[0];
sscanf(S, "%*[a-z ]%d %d",&x, &y);
}
else
{
sscanf(S, "%d %d", &x, &y);
}
doo(x, y, c);
if (i < n && i!=0 ) printf("\n");
}
return 0;
}@tsqx_nia_qute
by cxkssss678 @ 2022-10-24 09:21:35
@tsqx_nia_qute 没粘贴上，尴尬
by cxkssss678 @ 2022-10-24 09:25:36
@horray_for_bfs_dfs 没有我想写的是for(int i=0;i<4;i++) 然后在ide里第一次循环只输出换行，不进行输入，后来变成for(int i=0;i<=4;i++)就过了
by cxkssss678 @ 2022-10-24 09:32:02
@tsqx_nia_qute 这是AC的，多进行了一次循环
by cxkssss678 @ 2022-10-24 09:33:46
@Resolute_Faith 你是牛的,给你点赞
by zyz123789 @ 2022-10-28 15:26:34
你是我见到的第一个用gets的人