救救孩子只有二十分(ToT)

zsy_NKU @ 2022-11-03 10:56:10

#include<iostream>

using namespace std;

int main()
{
    int n,k,a=0,b=0,c=0,d;
    cin>>n>>k;
    for(int i=n;i;i--)
    {if(i%k==0){a+=i;c++;}
    else b+=i;}
    d=n-c;
    cout<<a*1.0/c<<" "<<b*1.0/d;

}

by happy_zero @ 2022-11-03 11:28:00

@zsy_NKU

 printf("%.1f %.1f",a*1.0/c,b*1.0/d);

输出保留一位小数

by zsy_NKU @ 2022-11-03 18:58:59

@zhuoyuxuan 我的源代码有保留一位的呀

by zsy_NKU @ 2022-11-03 20:16:39

@zsy_NKU 抱歉确实