Mrgteo79c @ 2022-11-07 20:34:36
#include<stdio.h>
int main()
{
int n,k;
double s=0;
scanf("%d",&k);
for(n=1;s<=k;n++)
{
s+=1.0/n;
}
printf("%d",n);
return 0;
}
by Mrgteo79c @ 2022-11-07 20:35:34
求大佬帮帮
by linyukun @ 2022-11-07 20:40:46
@Mrgteo79c s>k
不会立马跳出,会n++
,最后减掉就行吧。
by __QHY__ @ 2022-11-07 20:50:11
#include<stdio.h>
int main()
{
int n,k;
double s=0;
scanf("%d",&k);
for(n=1;s<=k;n++)
{
s+=1.0/n;
}
printf("%d",n);
return 0;
}
改为:
#include<stdio.h>
int main()
{
int n,k;
double s=0;
scanf("%d",&k);
for(n=1;s<=k;n++)
{
s+=1.0/n;
}
n -= 1;
printf("%d",n);
return 0;
}
就好了。
by Tu_es_trop_belle @ 2022-11-07 21:08:14
@q1haoyu 6
by Mrgteo79c @ 2022-11-08 18:18:50
@q1haoyu 谢谢
by Mrgteo79c @ 2022-11-08 18:19:12
@linyukun 谢谢