zsy_NKU @ 2022-11-10 19:16:02
#include<iostream>
#include<cmath>
#include <iomanip>
using namespace std;
int main()
{
int n,h=0,b=1;
cin >> n;
while(h<n*n)
{
int k;
b = 0-b;
cin >> k;
if (b == -1) {
for (int j = 1; j <= k; j++) {
cout << 0;
h++;
if (h % 7 == 0)
cout << endl;
}
}
if (b == 1) {
for (int j = 1; j <= k; j++) {
cout << 1;
h++;
if (h % 7 == 0)
cout << endl;
}
}
}
}
by bk1212 @ 2022-11-10 19:34:07
大哥,这是n*n的矩阵,要mod n