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P5735 【深基7.例1】距离函数

hct_ @ 2022-11-25 10:51:26

#include <bits/stdc++.h>
using namespace std;
int main(){
    double x1,x2,y1,y2,z1,z2;
    cin >>x1>>x2>>y1>>y2>>z1>>z2;
    cout <<fixed << setprecision(2)<<sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2))+sqrt((x1-x2)*(x1-x2)+(z1-z2)*(z1-z2))+sqrt((z1-z2)*(z1-z2)+(y1-y2)*(y1-y2));

    return 0;
}

by hct_ @ 2022-11-25 10:52:48

样例是对的啊,怎么回事?


by hct_ @ 2022-11-25 10:57:00

@AC_CSP 不太清楚


by hct_ @ 2022-11-25 11:01:32

谢谢,每日眼瞎(


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