整形二维数组输出一串不明所以的数

lnxjun1 @ 2022-12-07 22:13:11

#include <stdio.h>
int main()
{
    int x[50][80],y[80],n,flag=0;
    scanf("%d",&n);
    for(int i=0;i<=n-1;i++)
    {
        x[i][0]=1;
    }

    for(int k=0;k<=n-1;k++)
    {
        for(int j=79;j>=0;j--)
        {
            printf("%d",x[k][j]);               
        }
        printf("\n");
    }
    return 0;
}

by __er @ 2022-12-07 22:14:39

@lnxjun1 因为会爆int

by __er @ 2022-12-07 22:15:01

@lnxjun1 还会爆long long（

开了long long也去见祖宗

by lnxjun1 @ 2022-12-07 22:15:41

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有问题的一部分输出

by VitrelosTia @ 2022-12-07 22:16:41

@lnxjun1

如果希望通过本题，请继续学习第八章高精度的知识。

by lnxjun1 @ 2022-12-07 22:16:47

@__er 佬你看我下面的 不是你说的那种原因

by lnxjun1 @ 2022-12-07 22:23:26

@VT_SODC3DC3BSLF 我用的方法的确是用数组将每一位的数字一个一个输出.但我的问题并不在那里，只是将数组每一列首元素初始化为1，代码就出了问题

by Strelitzia_ @ 2022-12-07 22:24:50

数组定义在主函数里会随机赋值，移到主函数外即可。

by lnxjun1 @ 2022-12-07 22:26:44

@Strelitzia_ 佬，活了！ 多问一嘴，为什么前面一个不会随机赋值？

by Wangzj512 @ 2022-12-07 22:49:23

@lnxjun1 操作系统分配内存的时候，对两种（全局和局部）变量的处理方式不一样。全局变量是从一块暂时未使用的内存 (忘记叫啥了) 里开辟空间，所以全都是0（简单来说，找一块断电的内存重新通电）。而局部变量是从一块刚刚用过的内存里划出来的，里面的值无法确认来源，故为随机值。

（本人其实很菜，N年之前OI教练提过一嘴，现在只记得这么点了）