求助，为什么只有60分

linlin6 @ 2022-12-14 21:38:09

#include<iostream>
using namespace std;
int p,q,r,a,b,c,num,n[10],t=0;

void chai(int x)
{
    while (x != 0)
    {
        num = x % 10;
        x = x / 10;
        n[num]++;
    }
}
int main()
{
    cin >> p >> q >> r;
    if (p < q && q < r)
    {
        for (int i = 1; i <= 9; i++)
            for (int j = 1; j <= 9; j++)
                for (int k = 1; k <= 9; k++)
                {
                    a = 100 * i + 10 * j + k;
                    b = (q / p) * a;
                    c = (r / p) * a;
                    chai(a);
                    chai(b);
                    chai(c);
                    if (n[1] == 1 && n[2] == 1 && n[3] == 1 && n[4] == 1 && n[5] == 1 && n[6] == 1 && n[1] == 1 && n[7] == 1 && n[8] == 1 && n[9] == 1)
                    {
                        cout << a << " " << b << " " << c << endl;
                        t++;
                    }
                    for (int m = 0; m <= 9; m++)
                    {
                        n[m] = 0;
                    }
                }
        if (t == 0)
            cout << "No!!!";
    }
    return 0;
}

by bobosolomon @ 2022-12-16 14:32:35

如果p q r 不符合要求p < q && q < r，那么，你这个只会输出No!!!;这样是不对的，你可以枚举1-1000的每一个数，然后a,b,c分别a = i * p, b = i * q, c = i * r，那么再用你那个是可以的。

by shuyuan2016 @ 2022-12-18 17:27:46

#include<cstdio>
#include<iostream>
#include<algorithm>
using namespace std;
int a[10];
int A,B,C;
int main(){
    cin>>A>>B>>C;
    for(int i=1;i<=9;i++)a[i]=i;
    int cnt=0;
    do{
        int x,y,z;
        x=100*a[1]+10*a[2]+a[3];
        y=100*a[4]+10*a[5]+a[6];
        z=100*a[7]+10*a[8]+a[9];
        if(y*A==B*x&&A*z==C*x){
            printf("%d %d %d\n",x,y,z);
            cnt++;}
    }while(next_permutation(a+1,a+10));
    if(cnt==0)cout<<"No!!!";
    return 0;
}

by int_stl @ 2022-12-21 18:34:30

#include <iostream>
#include <algorithm>
using namespace std;
typedef long long LL;
int a[10];
int main() {
    LL A, B, C, x, y, z, cnt = 0;
    cin >> A >> B >> C;
    if (A == 0 && B == 0 && C == 0) {
        cout << "No!!!";
        return 0;
    }
    for (int i = 1; i <= 9; i++) {
        a[i] = i;
    }
    do {
        x = a[1] * 100 + a[2] * 10 + a[3];
        y = a[4] * 100 + a[5] * 10 + a[6];
        z = a[7] * 100 + a[8] * 10 + a[9];
        if (x * B == y * A && y * C == z * B) {
            cout << x << " " << y << " " << z << endl, cnt++;
        }
    } while (next_permutation(a + 1, a + 10));
    if (!cnt) cout << "No!!!";
}