jingwenMC @ 2018-08-12 16:47:23
先话不多说,上结果
cout<<"1"<<"ac"<<endl;
cout<<"2"<<"tle"<<endl;
cout<<"3"<<"ac"<<endl;
cout<<"4"<<"ac"<<endl;
cout<<"5"<<"ac"<<endl;
cout<<"6"<<"ac"<<endl;
cout<<"7"<<"ac"<<endl;
cout<<"8"<<"ac"<<endl;
cout<<"9"<<"wa"<<endl;
cout<<"10"<<"tle"<<endl;
源代码:
#include<iostream>
using namespace std;
int main()
{
int date1,date2;
cin>>date1>>date2;
if(date1==date2)
{
int x,y,z;
x=date1;
y=0;
while(x>0)
{
z=x%10;
x=x/10;
y=y*10+z;
}
if(date1==y)cout<<"1"<<endl;
else cout<<'0'<<endl;
return 0;
}
else if (date1 < date2)
{
//*
int dd[13]= {0,31,28,31,30,31,30,31,31,30,31,30,31};
int x, y, z,c=0;
for (int i = date1; i <= date2; i++)
{
int modi=i%10000/100,di=i%100;
x = i;
y = 0;
while (x>0)
{
z = x % 10;
x = x / 10;
y = y * 10 + z;
}
if (i == y&&modi<13&&di<dd[modi])
{
c++;
}
}
//if(c==2)c=9;
cout <<c<< endl;
return 0;//*/
}
}
请问该如何改进?
by jingwenMC @ 2018-08-12 16:48:20
by Smile_Cindy @ 2018-08-12 16:54:12
@jingwenMC
你忘了判date1>date2
by ylxmf2020 @ 2018-08-12 17:39:02
楼上大佬
by CHY123 @ 2018-08-29 09:45:55
@Alpha 题目不是保证了 date1 —定不晚于date2 吗
by Smile_Cindy @ 2018-08-29 19:58:52
@jingwenMC
首先,你如果从date1枚举到date2会有很多重复累赘的情况,其次在date1和date2之间会有不在它们范围内的日期。
by jingwenMC @ 2018-10-26 22:32:09
@Alpha 谢谢!
by cs613 @ 2019-11-16 11:22:24
@jingwenMC 枚举年份就行了