ragwort @ 2023-02-15 23:01:32
#include <bits/stdc++.h>
#define int long long
using namespace std;
const int N = 1e5+10;
int t[N*4],a[N],n,m;
inline void build(int k,int l,int r){
if(l == r){
t[k] = a[l];
return ;
}
int mid = l + r >> 1;
build(k*2,l,mid);
build(k*2+1,mid+1,r);
t[k] = t[k*2]+t[k*2+1];
}
inline void update(int k,int l,int r,int v){
if(l == r){
t[k] += v;
return ;
}
int mid = l + r >> 1;
update(k*2,l,mid,v);
update(k*2+1,mid+1,r,v);
t[k] = t[k*2] + t[k*2+1];
}
inline int query(int k,int l,int r,int x,int y){
if(x <= l && y >= r) return t[k];
int mid = l+r>>1,res=0;
if(x <= mid) res = query(k*2,l,mid,x,y);
if(y > mid) res += query(k*2+1,mid+1,r,x,y);
return res;
}
signed main() {
cin >> n >> m;
for(int i = 1; i <= n; i++)
cin >> a[i];
int x,y,z;
while(m--){
cin >> x;
if(x == 2){
cin >> x >> y;
cout << query(1,1,n,x,y) << endl;
}else{
cin >> x >> y >> z;
update(1,x,y,z);
}
}
return 0;
}
谢谢
by Placy @ 2023-02-16 06:33:12
懒得写的话用树状数组混过去也行