linyiyi123456 @ 2023-03-01 01:29:58
#include<stdio.h>
#include<math.h>
int main()
{
int a[100],m=0,i,sum=0,n;
scanf("%d",&n);
while(n>0)
{
a[m++]=n%10;
n/=10;
}
int m1=m;
for(i=0;i<m;i++)
{
if(a[1]==0)
{
m1--;
continue;
}
else
{
sum+=a[i]*pow(10,m1-1);
m1--;
}
printf("%d",sum);
}
if(n<0)
{
printf("-%d",sum);
}
else
{
printf("%d",sum);
}
return 0;
}
by CCX_Ug @ 2023-03-01 08:28:21
标题党
by CCX_Ug @ 2023-03-01 08:30:12
如果n是负数的话那么前面的
while (n > 0)
就不会被执行
by CCX_Ug @ 2023-03-01 08:31:00
而且不建议用pow
by CCX_Ug @ 2023-03-01 08:33:18
AC记录
by linyiyi123456 @ 2023-03-03 01:46:18
#include<stdio.h>
#include<math.h>
int main()
{
int a[10],m=0,i,sum=0,n,n1;
scanf("%d",&n);
if(n==0)
{
printf("0");
}
else
{
n1=abs(n);
while(n1>0)
{
a[m++]=n1%10;
n1/=10;
}
int m1=m;
if(n<0)
{
printf("-");
}
for(i=0;i<m;i++)
{
if(a[i]==0)
{
if(a[i-1]==0)
{
continue;
}
}
else
{
printf("%d",a[i]);
}
}
}
return 0;
}
@the_player 麻烦大佬再帮我康康,7,9,10编译过不了
by CCX_Ug @ 2023-03-03 18:17:10
你这个交到你谷上不会CE
这里
if(a[i]==0)
{
if(a[i-1]==0)
{
continue;
}
}
遇到0就不会输出
其实我不是dalao
by CCX_Ug @ 2023-03-03 18:17:56
再改一改\~~
by linyiyi123456 @ 2023-03-04 00:22:57
@the_player 我这边0可以出
by zhangboyuan0 @ 2023-03-13 21:19:46
#include <bits/stdc++.h>
using namespace std;
int main(){
int num;
cin >> num;
if(num == 0){
cout << 0;
return 0;
}
if(num < 0){
cout << '-';
num = -num;
}
while(num % 10 == 0 && num > 0){
num = num / 10;
}
while(num > 0){
cout << num % 10;
num = num / 10;
}
return 0;
}