qingkongd_Rj @ 2023-03-07 20:17:22
#include <iostream>
#include <cstdio>
#include <iomanip>
#include <cstring>
#include <cmath>
#include <string>
using namespace std;
char a[1001] , b[1001];
int a1[1001], b1[1001], c[1001];
int main(){
cin >> a >> b;
int lena = strlen(a);
int lenb = strlen(b);
for (int i = 0; i < lena; i++){
a1[lena - 1 - i] = a[i] - 48;
}
for (int i = 0; i < lenb; i++){
b1[lenb - 1 - i] = b[i] - 48;
}
for (int i = 0; i < lenb; i++){
int x = 0;
for(int j = 0; j < lena; j++){
c[i+j] += b1[i] * a1[j] + x;
x = c[i + j] /10;
c[i + j] %= 10;
}
c[i + lena] = x;
}
int index = 0;
for(int i = lena + lenb - 1; i >= 0; i--){
if(c[i] != 0){
index = i;
break;
}
}
for(int i = index; i >= 0; i--){
cout << c[i];
}
return 0;
}
by Seapeac @ 2023-03-07 20:45:33
将输入的字符串转为数组后,当成多个高*单来算。
by haijun_ @ 2023-03-12 19:14:59
python
a=int(input())
b=int(input())
print(a*b)你看多简单
by zengqhuai @ 2023-05-13 15:17:45
@haijun_print(int(input())*int(input()))一行就可以过