不懂，一直runtime error

_1698abc @ 2023-03-08 19:31:08

#include<iostream>
#include<algorithm>
#include<iomanip>
#include<cmath>
using namespace std;
int main()
{
    float num=0,pin,cha=0,b=0,c=99999999;
    int n;
    float a[200] = {0};
    cin >> n;
    for (int i = 0; i <= n - 1; i++)
    {
        cin >> a[i];
    }
    for (int i = 0; i <= n - 1; i++)
    {
        b = max(b, a[i]);
        c = min(c, a[i]);
        num += a[i];
    }
    pin = (num - b - c) / (n - 2);
    float p;
    for (int j = 0; j <= n - 1; j++)
    {
        if (a[j] == b || a[j]==c)
        {
            continue;
        }
        p = abs(a[j] - pin);
        cha = max(cha, p);

    }
    cout << fixed << setprecision(2) << pin << " " << cha;

}

by WA_sir @ 2023-03-08 19:48:41

@_1698abc n \leq 300

你是 Wrong Answer 罢

by tangguo_yyds @ 2023-03-08 19:55:05

#include<iostream>
#include<algorithm>
#include<iomanip>
#include<cmath>
using namespace std;
int main()
{
    double num=0,pin,cha=0,b=0,c=99999999;
    int n,x,y;
    double a[310] = {0};
    cin >> n;
    for (int i = 0; i <= n - 1; i++)
    {
        cin >> a[i];
        if(a[i]<c){
            c=a[i];
            x=i;
        }
        if(a[i]>b){
            b=a[i];
            y=i;
        }
        num += a[i];
    }
    pin = (num - b - c) / (n - 2);
    double p;
    for (int j = 0; j <= n - 1; j++)
    {
        if (j!=x&&j!=y)
        {
           p = abs(a[j] - pin);
        cha = max(cha, p);
        }
    }
    cout << fixed << setprecision(2) << pin << " " << cha;
}

by tangguo_yyds @ 2023-03-08 19:58:54

@_1698abc

数组开小了，而且只去掉一个最大值和最小值，

if (a[j] == b || a[j]==c)

可能去掉不止一个最大值和最小值

而且可以边输入边找最大值和最小值，并加总和

by tangguo_yyds @ 2023-03-08 19:59:37

题目中只要求去掉一个最大值和最小值

by _1698abc @ 2023-03-09 16:13:58

@WA_sir 好的，谢谢

by _1698abc @ 2023-03-09 16:14:24

@tangguo_yyds 感谢感谢