lcbridge @ 2023-04-01 20:31:14
感觉思路没啥问题呀?
#include <bits/stdc++.h>
#define int long long
using namespace std;
const int maxn=100000+5;
const int maxm=200000+5;
int n,m,s,dis[maxn],f[maxn],b,maxx;
struct edge{
int to,w;
};
vector <edge> g[maxm];
priority_queue <pair<int,int> > q;
bool vis[maxn];
bool dij(int k){
if(k<f[1])return false;
for(int i=1;i<=n;i++)dis[i]=0x7ffffffff;
dis[1]=0;
q.push(make_pair(0,1));
while(!q.empty()){
int x=q.top().second;
q.pop();
if(vis[x])continue;
vis[x]=1;
for(int i=0;i<g[x].size();i++){
int to=g[x][i].to;
if(f[to]>k)continue;
if(dis[to]>dis[x]+g[x][i].w){
dis[to]=dis[x]+g[x][i].w;
q.push(make_pair(-dis[to],to));
}
}
}
return dis[n]>=b;
}
signed main(){
scanf("%lld%lld%lld",&n,&m,&b);
for(int i=1;i<=n;i++){
scanf("%lld",&f[i]);
maxx=max(maxx,f[i]);
}
for(int i=1;i<=m;i++){
int u,v,w;
scanf("%lld%lld%lld",&u,&v,&w);
g[u].push_back({v,w});
g[v].push_back({u,w});
}
int l=0,r=maxx+1,mid,ans=-1;
while(l<=r){
mid=(l+r)>>1;
if(dij(mid)){
r=mid-1;
ans=mid;
}
else l=mid+1;
}
if(ans==-1)printf("AFK");
else printf("%lld",ans);
return 0;
}
by Istruggle @ 2023-08-02 13:02:06
借个帖
我也是这么写的,开O2能过几个,帮我也看一下。
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
ll n,m,b,f[100005],cnt=0,head[100005],r,l;
ll dis[100005];
ll vis[100005];
struct edge
{
ll v,w,next;
}e[500005];
void addedge(ll u,ll v,ll w)
{
e[++cnt].v=v;
e[cnt].w=w;
e[cnt].next=head[u];
head[u]=cnt;
}
struct node{
ll u,d;
bool operator <(const node&rhs) const{
return d>rhs.d;
}
};
bool dij(ll temp){
if(f[1]>temp) return false;
memset(vis,0,sizeof(vis));
for(ll i = 1;i<=n;i++) dis[i]=0x3f;
priority_queue<node> q;
q.push((node){1,0});
dis[1]=0;
while(!q.empty())
{
node fr=q.top(); q.pop();
ll u = fr.u;
ll d= fr.d;
if(vis[u]) continue;
vis[u]=1;
for(ll i = head[u];i;i=e[i].next){
ll y=e[i].v;
if(e[i].w>temp) continue;
if(dis[y]>dis[u]+e[i].w){
dis[y]=dis[u]+e[i].w;
if(!vis[y])
{
q.push((node){y,dis[y]});
}
}
}
}
if(dis[n]<b) return true;
else return false;
}
int main()
{
scanf("%d%d%d",&n,&m,&b);
for(ll i= 1;i<=n;i++)
scanf("%d",&f[i]),r=max(r,f[i]);
for(ll i = 1;i<=m;i++){
ll a,b1,c;
scanf("%d%d%d",&a,&b1,&c);
if(a==b1) continue;
addedge(a,b1,c);
addedge(b1,a,c);
}
int ans=-1;
l=max(f[1],f[n]);
while(l<=r){
ll mid=(l+r)>>1;
if(dij(mid)) r=mid-1,ans=mid;
else l=mid+1;
}
if(ans==-1) {
cout<<"AFK";return 0;
}
printf("%d",ans);
return 0;
}