YYYabc @ 2023-04-29 19:48:56
#include <iostream>
using namespace std;
int f(int x)
{
if (x <= 1) return 1;
return x * f(x - 1);
}
int main()
{
int n;
cin >> n;
int sum = 0;
for (int i = 1; i <= n; i++)
{
sum += f(i);
}
cout << sum << endl;
return 0;
}by zfj123456 @ 2023-04-29 19:57:34
要高精度啊！！！题里都明确说了@YYYabc
by sherry_lover @ 2023-04-29 20:24:20
@YYYabc 高精度！！！
by chenxinuo @ 2023-05-04 19:52:46
高精度！！！！！！7
by kkkkksc03_is_sb @ 2023-05-10 19:18:49
高精度！！！
by zzhlzy200912 @ 2023-05-13 15:47:33
@YYYabc python一行就能搞定 print(reduce(lambda x,y:x+y,[reduce(lambda x,y:x*y,range(1,i+1)) for i in range(1, int(raw_input())+1)]))
by cyt_666 @ 2023-05-21 22:39:54
@zzhlzy200912 tql