QwQ，蒻蒻求助！20分

Max6700 @ 2023-05-03 11:31:35

#include<bits/stdc++.h>
using namespace std;

int n;
char c[100000];
int a[100000];

int main(){
    cin>>n;

    int i=1;
    while(cin>>c[i])
    {
        a[i]=int(c[i]-'0');
        i++;
    }

    int now1=0;
    int now2=1;

    while(now2<=i)
    {
        for(int j=1;j<=a[now2];j++)
        {
            now1++;
            cout<<(now2+1)%2;
            if(now1%n==0)cout<<"\n";
        }
        now2++;
    }

    return 0;
}

by D0000 @ 2023-05-03 12:01:29

输入的问题 可以以字符串读入

by Max6700 @ 2023-05-03 12:06:44

@cdrdyl 嗯？

by Max6700 @ 2023-05-03 12:07:03

@cdrdyl [不解]

by Max6700 @ 2023-05-03 12:12:06

@cdrdyl 字符串遇到空格会停止读入……

by D0000 @ 2023-05-03 13:35:07

有了，判断输入的数的总和，如果等于n*n,就停止

by Max6700 @ 2023-05-03 21:12:24

@cdrdyl 嗯？听起来好像可刑，我试试

by Max6700 @ 2023-05-03 21:13:57

@cdrdyl 哇！！！过了！thx！！！

by Max6700 @ 2023-05-03 21:17:10

@cdrdyl AC力！

#include<bits/stdc++.h>
using namespace std;

int n;
string s;
int a[100000];

int sum;

int main(){
    cin>>n;

    int i=1;

    while(sum<n*n)
    {
        cin>>a[i];
        sum+=a[i];
        i++;
    }

    int now1=0;
    int now2=1;

    while(now2<=i)
    {
        for(int j=1;j<=a[now2];j++)
        {
            now1++;
            cout<<(now2+1)%2;
            if(now1%n==0)cout<<"\n";
        }
        now2++;
    }

    return 0;
}