徐殿崴2011 @ 2023-05-28 19:31:49
#include<iostream>
using namespace std;
long long n, f[1000005], tmp;
int main() {
cin >> n;
f[1] = 1;
f[2] = 2;
for(int i = 3;i <= n; i++)
{
f[i] = f[i - 1] + f[i - 2];
}
cout << f[n] ;
}
很急,在线等
by wyh0413 @ 2023-06-01 07:08:02
高精度加法
by biggay002 @ 2023-06-20 16:00:33
没有高精度ww