样例和第一个点都是对的，但全是WA,哪位大佬看看

#include <bits/stdc++.h>
using namespace std;
char s[105] , f;
int x,y,n;
int maxn = -1 , minn = 1 << 30 ;

void init()//输入 
{
    int cnt = 0 , i = 0 , temp = 0;
    bool flag = true;
    fgets(s,sizeof(s),stdin);
    if(s[0] < '0' || s[0] > '9') f = s[0] , i  = 2;
    int len = strlen(s);
    x = 0 , y = 0;
    for(;i < len; i++)//拆分字符串，转成数字
    {
        if(s[i] != ' ' && s[i] != '\n')
        {
            temp *= 10;
            temp += int(s[i] - 48);
        }
        else 
        {
            if(flag) x = temp , flag = false;
            else y = temp;
            temp = 0;
        }
    }
    if(temp != 0) y = temp;//最后一次的字符串没有换行符 
}
int cnt(int z)
{
    int sum = 0;
    while(z)
    {
        z /= 10;
        sum++;
    }
    return sum;
}
int main()
{
    int ans;
    scanf("%d\n",&n);
    for(int i = 1;i <= n;i++)
    {
        init();
        ans = 0;
        if(f == 'a') ans = x + y , cout<<x<<"+"<<y<<"="<<ans<<endl , cout<<2+cnt(x)+cnt(y)+cnt(ans)<<endl;
        else if(f == 'b')
        {
            ans = x - y ;
            cout<<x<<"-"<<y<<"="<<ans<<endl;
            if(ans >= 0) cout<<2+cnt(x)+cnt(y)+cnt(ans)<<endl;
            else cout<<3+cnt(x)+cnt(y)+cnt(ans)<<endl;
        } 
        else ans = x * y , cout<<x<<"*"<<y<<"="<<ans<<endl , cout<<2+cnt(x)+cnt(y)+cnt(ans)<<endl;
    } 
    return 0;
 }