~~压行~~
by Fze_8 @ 2023-06-06 18:28:17
[第二篇题解](https://www.luogu.com.cn/blog/over-knee-socks/solution-b2043)
by H_Kaguya @ 2023-06-06 18:28:19
```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
int n;
cin>>n;
if(n%3==0) cout<<"3 ";
if(n%5==0) cout<<"5 ";
if(n%7==0) cout<<"7 ";
return 0;
}
```
by AnOIer @ 2023-07-11 07:00:13
```c
#include <stdio.h>
#include <stack>
#include <queue>
#include <vector>
#include <list>
#include <map>
using namespace std;
int a;
bool flag = true;
int main(){
scanf("%d" , &a);
if(a % 3 == 0){
printf("3 ");
flag = false;
}
if(a % 5 == 0){
printf("5 ");
flag = false;
}
if(a % 7 == 0){
printf("7 ");
flag = false;
}
if(flag) printf("n");
return 0;
}
by printf_ @ 2023-07-17 17:39:05
没必要导入那么多头文件
by xieyzy @ 2023-07-31 15:57:11
```
#include<bits/stdc++.h>
using namespace std;
int x,f=0;
int main(){
cin>>x;
if(x%3==0){
f=1;//如果x能被整除那么f+1，f用来判断三个条件的成立
cout<<"3 ";
}
if(x%5==0){
f=1;
cout<<"5 ";//if判断是从小到大比的，不需要比大小
}
if(x%7==0){
f=1;
cout<<"7 ";
}
if(f==0){//三个条件都没成立，f就=0 输出n；
cout<<"n";
}
return 0;
}
```
by Tairitsu_Cat @ 2023-08-12 17:26:07
循环应该可以做吧？```
#include<iostream>
using namespace std;
long long n,m;
int main() {
cin>>n;
if(n%3==0&&n%5==0&&n%7==0){
printf("%d %d %d",3, 5 ,7);
}else if(n%3==0&&n%5==0){
printf("%d %d",3,5);
}else if(n%3==0&&n%7==0){
printf("%d %d",3,7);
}else{
printf("%d %d",5,7);
}
return 0;
}
```
by jiangjialeqaz @ 2023-08-16 21:53:26