求dalao看看 90

牛寺另刂6 @ 2018-09-01 13:03:51

#include<iostream>
using namespace std;
int main()
{
    int n,k,l;
    cin>>n>>k;
    l=n+n/k;
    if(n/k>=k)
    l=n+n/k+n/k/k;
    cout<<l;
}

by __Hacheylight__ @ 2018-09-01 13:16:44

cin>>n>>k;

cout<<n+(n-1)/(k-1);

by __Hacheylight__ @ 2018-09-01 13:16:49

@牛寺另刂6

by 牛寺另刂6 @ 2018-09-01 13:48:13

@Harryheqg 谢谢