zlfpass @ 2023-06-15 16:33:27
date1=input()
date2=input()
aa=[0,31,29,31,30,31,30,31,31,30,31,30,31]
bb=[0,31,28,31,30,31,30,31,31,30,31,30,31]
year1=date1[:4]
year2=date2[:4]
def qn(year1,year2):
n=0
while int(year1)<=int(year2):
#print(int(year1[::-1][:2]))
if int(year1[::-1][:2])<1 or int(year1[::-1][:2])>12:
year1=str(int(year1)+1)
#print(year1)
else:
#print("xia",year1)
if (int(year1)%4==0 and int(year1)%100!=0) or (int(year1)%4==0):
for i in range(1,len(aa)):
for j in range(1,aa[i]+1):
if (year1+str(i).zfill(2)+str(j).zfill(2))==(year1+str(i).zfill(2)+str(j).zfill(2))[::-1]:
#print((year1+str(i).zfill(2)+str(j).zfill(2)))
n+=1
#print(n)
if (year1+str(i).zfill(2)+str(j).zfill(2))==date2:
return n
else:
for i in range(1,len(bb)):
for j in range(1,bb[i]+1):
if (year1+str(i).zfill(2)+str(j).zfill(2))==(year1+str(i).zfill(2)+str(j).zfill(2))[::-1]:
#print((year1+str(i).zfill(2)+str(j).zfill(2)))
n+=1
#print(n)
if (year1+str(i).zfill(2)+str(j).zfill(2))==date2:
return n
year1=str(int(year1)+1)
return n
n=qn(year1,year2)
print(n)by HLR20120422 @ 2023-06-15 17:08:05
#include <iostream>
#include <string>
using namespace std;
class _
{
public:
int y;
int m;
int d;
string ymd;
};
void split(string s,int &a,int &b,int &c){
a=(s[0]-'0')*1000+(s[1]-'0')*100+(s[2]-'0')*10+(s[3]-'0');
b=(s[4]-'0')*100+(s[5]-'0');
c=(s[6]-'0')*100+(s[7]-'0');
}
bool run(int runnian)
{
if(runnian%4==0&&runnian%100)return true;
if(runnian%400==0)return true;
return false;
}
int main()
{
int tpl=0;
_ startday;
_ endday;
int nian,yue,ri;
cin>>startday.ymd>>endday.ymd;
split(startday.ymd,startday.y,startday.m,startday.d);
split(endday.ymd,endday.y,endday.m,endday.d);
int i,s;
int c=0;
for(i=startday.y;i<=endday.y;i++)
{
nian=i;
yue=(nian%10)*10+(nian/10%10);
ri=(nian/100%10)*10+(nian/1000%10);
c++;
s=0;
if(yue>12||yue<1||ri<1||ri>31)s=1;
if(yue==4||yue==6||yue==9||yue==11)if(ri>30)s=1;
if(run(nian)==false)if(yue==2)if(ri>28)s=1;
if(run(nian)==true)if(yue==2)if(ri>29)s=1;
if(nian==startday.y&&(yue<startday.m&&ri<startday.d))s=1;
if(nian==endday.y&&(yue>endday.m&&ri>endday.d))s=1;
c=c-s;
}
cout<<c<<endl;
}