20110915_260 @ 2023-07-02 09:26:43
#include<bits/stdc++.h>
using namespace std;
long long a[5005];
int main(){
long long n;
cin>>n;
a[1]=1;
a[2]=2;
for(int i=3;i<=n;i++){
a[i]=a[i-1]+a[i-2];
}
cout<<a[n];
return 0;
}by Henry2012 @ 2023-07-02 09:27:34
开高精
by Henry2012 @ 2023-07-02 09:28:25
by linjunye @ 2023-07-02 09:30:17
题解里都提到高精度了，显然不是longlong就能搞定的。
by jzl15880255743 @ 2023-07-02 10:33:45
@20110915_260 数据范围太大了
by 20110915_260 @ 2023-07-02 10:35:05
我真的会谢谢你！ @jzl15880255743
by jzl15880255743 @ 2023-07-02 10:36:08
@20110915_260 不用谢
by 20110915_260 @ 2023-07-02 10:37:25
我必须要蟹蟹你！晚上去你家偷马桶盖！@jzl15880255743