bbluele @ 2023-07-07 14:40:28
#include<iostream>
using namespace std;
int z[10001], l, m, i, j, u, v, n;
int main()
{
cin >> l >> m;
for (i = 0; i < m; i++)
{
cin >> u >> v;
for (j = 0; j < l; j++)
{
if (j > u-1 && j < v+1)
{
z[j] = 1;
}
}
}
for (i = 0; i < l; i++)
{
if (z[i] == 1)
{
n++;
}
}
cout << l - n + 1;
//这个前三个点过不了,而下面这个只有前三个点能过;
//cout<<l-n;
}
by rnf5114 @ 2023-07-07 14:44:49
@bbluele 应该是≤l
by rnf5114 @ 2023-07-07 14:45:02
@bbluele
#include<iostream>
using namespace std;
int z[10010], l, m, u, v, n;
int main()
{
cin >> l >> m;
for (int i = 0; i < m; i++)
{
cin >> u >> v;
for (int j = 0; j <= l; j++)
{
if (j >=u && j <=v)
{
z[j] = 1;
}
}
}
for (int i = 0; i <= l; i++)
{
if (z[i] == 1)
{
n++;
}
}
cout << l - n + 1;
//这个前三个点过不了,而下面这个只有前三个点能过;
//cout<<l-n;
}
by rnf5114 @ 2023-07-07 14:45:13
求关