求助，不理解了

zhaoanqiEtayo @ 2023-07-08 06:24:53

#include<stdio.h>
#include<stdlib.h>
int main()
{
    int n,k,i,sum1,sum2,a,q;
    double b,c;
    scanf("%d %d",&n,&k);
    sum1=0;sum2=0;
    a=0;q=0;
    for(i=1;i<=n;i++)
    {
        if(i%k==0)
        {
            a++;
            sum1=sum1+i;
            b=sum1/a*1.0;
        }
        else
        {
            q++;
            sum2=sum2+i;
            c=sum2/q*1.0;
        }
    }
    printf("%.1lf %.1lf",b,c);
    return 0;
}

by zhongboxuan123 @ 2023-07-08 06:46:25

@zhaoanqiEtayo 把b和q的计算放到循环外

by zhaoanqiEtayo @ 2023-07-08 09:13:12

@zhongboxuan123 谢谢！但可以解释一下为什么这样写吗？萌新不理解

by zhaoanqiEtayo @ 2023-07-08 09:16:15

#include<stdio.h>
#include<stdlib.h>
int main()
{
    int n,k,i,sum1,sum2,a,q;
    double b,c;
    scanf("%d %d",&n,&k);
    sum1=0;sum2=0;
    a=0;q=0;
    for(i=1;i<=n;i++)
    {
        if(i%k==0)
        {
            a++;
            sum1=sum1+i;
        }
        else
        {
            q++;
            sum2=sum2+i;
        }
    }
    b=sum1/a*1.0;
    c=sum2/q*1.0;
    printf("%.1lf %.1lf",b,c);
    return 0;
}

@zhongboxuan123 好像还是不对呀

by zhongboxuan123 @ 2023-07-08 10:03:16

@zhaoanqiEtayo 精度丢失问题，用你的代码输出1000 7这组数据的时候输出了500.0，说明精度丢失，我给出的建议是把a和q改成double，然后先1.0，后面`b=sum1/a1.0; c=sum2/q*1.0;就不用再乘了`

by zhongboxuan123 @ 2023-07-08 10:03:50

@zhaoanqiEtayo 这是通过记录1

by zhaoanqiEtayo @ 2023-07-08 10:19:30

@zhongboxuan123 感谢

by Griseo1221 @ 2023-07-31 15:15:55

@zhaoanqiEtayo 我超 穹