求帮忙找不同,用第一个函数满分,第二个50分,哪里不同呀

P1093 [NOIP2007 普及组] 奖学金

KANGAR00 @ 2023-07-08 10:39:07


bool cmp(student a,student b)
{
    if(a.sum>b.sum) return 1;
    else if(a.sum<b.sum) return 0;
    else
    {
        if(a.chinese>b.chinese) return 1;
        else if(a.chinese<b.chinese) return 0;
        else
        {
            if(a.id>b.id) return 0;
            else return 1;
        }
    }
}
bool cmp(student x,student y)
{
    if(x.sum==y.sum)
    {
        if(x.chinese<y.chinese)
        return x.sum<y.sum;
        else if(x.chinese == y.chinese)
        {
            if(x.id>y.id)
            return x.sum<y.sum;
        }
        return x.sum>y.sum;
    }
    return x.sum>y.sum;
}
----------------------------------------------
下面是代码,也就是得50分的,但是替换成第一个函数就满分了
#include<bits/stdc++.h>
using namespace std;
struct student
{
    int id;
    int chinese;
    int math;
    int english;
    int sum;
};
bool cmp(student x,student y)
{
    if(x.sum==y.sum)
    {
        if(x.chinese<y.chinese)
        return x.sum<y.sum;
        else if(x.chinese == y.chinese)
        {
            if(x.id>y.id)
            return x.sum<y.sum;
        }
        return x.sum>y.sum;
    }
    return x.sum>y.sum;
}
int main()
{
    int n;
    int c,i;
    cin>>n;
    student *stu = new student[n+1];
    for(i=1;i<=n;i++)
    {
        cin>>stu[i].chinese>>stu[i].math>>stu[i].english;
        stu[i].sum = stu[i].chinese+stu[i].math+stu[i].english;
        stu[i].id =i;
    }
    sort(stu+1,stu+n+1,cmp);
    for(i=1;i<=5;i++)
    {
        cout<<stu[i].id<<" "<<stu[i].sum<<endl;
    }
}

by Clever_Ivory @ 2023-07-08 11:00:21

bool cmp(student x,student y)
{
    if(x.sum==y.sum)
    {
        if(x.chinese<y.chinese)
        return x.sum<y.sum;
        else if(x.chinese == y.chinese)
        {
            if(x.id>y.id)
            return x.sum<y.sum;
        }
        return x.sum>y.sum; //这个地方应该是返回1的,但是你现在返回的是x.sum > y.sum,可是这个分支中x.sum == y.sum,所以返回的肯定是0啊。改成1就行了吧。
    }
    return x.sum>y.sum;
}

by KANGAR00 @ 2023-07-08 14:33:12

@jwang69 明白了,谢谢大佬


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