求助！#3#4

shangyuang @ 2023-07-14 21:25:04

#include<bits/stdc++.h>
using namespace std;
int n,i,j,k,len;
string s;
char huan(char a){
    while(a>'z'){
        a=char(a-'z'+'a'-1);
    }
    return a;
}
int main(){
    scanf("%d",&n);
    cin>>s;
    len=s.length();
    for(i=0;i<len;++i){
        s[i]=huan(s[i]+n);
    }
    cout<<s;
    return 0;
}

by Slient_QwQ @ 2023-07-14 21:35:48

#include<bits/stdc++.h>
using namespace std;
int n,i,j,k,len;
char s[114514];
int main(){
    scanf("%d",&n);
    cin>>s;
    len=strlen(s);
    for(i=0;i<len;++i){
        for(j=1;j<=n;j++)//必须得用for，不知道为什么直接减过不了
        {
            s[i]++;
            if(s[i]>'z')s[i]-=26;
        }
    }
    cout<<s;
    return 0;
}

by ccf_0102 @ 2023-07-15 18:15:20

@shangyuang z的ASCII值很大，再加就爆成负数了

by shangyuang @ 2023-07-15 18:16:18

@ccf_0102 怎么解决呢

by ccf_0102 @ 2023-07-15 18:17:26

@shangyuang 可以像一楼一样，或者判断条件改成a不在'a'-'z'之间

by shangyuang @ 2023-07-15 18:18:51

@ccf_0102 哦，我试试

by shangyuang @ 2023-07-15 18:22:14

@ccf_0102 ac了，谢谢喵

by ccf_0102 @ 2023-07-15 18:23:03

@shangyuang 特地把关于关注我的内容删了然后重发是吧（

by shangyuang @ 2023-07-15 18:24:28

@ccf_0102 但我还是关注你了喵

by ccf_0102 @ 2023-07-15 18:25:30

@shangyuang 是这样的喵

by shangyuang @ 2023-07-15 18:28:24

@ccf_0102 能给我一个关注吗喵