60分求助

Rmghcz @ 2023-07-20 22:22:36

#include<iostream>
using namespace std;
double i,sum;
int main()
{
    cin>>i;
    if(i<=150)
    {
        sum=i*0.4463;
        printf("%.1f",sum);
    }
    else if(i>=151&&i<=400)
    {
        sum=150*0.4463+(i-150)*0.4663;
        printf("%.1f",sum);
    }
    else
    {
        sum=150*0.4463+400*0.4663+(i-400)*0.5663;
        printf("%.1f",sum);
    }
    return 0;
}

by bk1212 @ 2023-07-20 22:49:09

@Rmghcz

sum=150*0.4463+400*0.4663+(i-400)*0.5663;

这行代码写错了哦，应该写为

sum=150*0.4463+250*0.4663+(i-400)*0.5663;

因为他是151~400这个范围的电费是0.4663元，而你写成了400，应该是400-150=250AC记录

by __LiChangChao__ @ 2023-07-20 22:52:35

@Rmghcz

400*0.4663

by Rmghcz @ 2023-07-20 22:53:08

@bk1212 好滴，谢谢！

by Rmghcz @ 2023-07-20 22:56:36

@changwenxuan不好意思，我太粗心了，当时没有考虑这个