本辣鸡不会做呀，求大佬解答（B2047 分段函数）

fty123456___ @ 2023-08-03 19:34:11

by ATZdhjeb @ 2023-08-03 19:39:56

题解：你好！

by yzm0325 @ 2023-08-03 19:41:40

@fty123456___ 参考题解的思路

by LEle0309 @ 2023-08-03 20:12:20

@fty123456___

核心代码：

double f(double x)
{
    double y;
    if(0<=x&&x<5)y=-x+2.5;
    if(5<=x&&x<10)y=2-1.5*(x-3)*(x-3);
    if(10<=x&&x<20)y=x/2-1.5;
    return y;
}

模拟即可请勿抄袭

by LEle0309 @ 2023-08-03 20:14:08

违规紫衫

by 2041luyancheng @ 2023-08-14 15:56:47

像这种分段的题目，用if就好了

by 2024yejinghong @ 2023-08-21 16:07:42

#include<bits/stdc++.h>
using namespace std;
int main()
{
    double x;
    cin>>x;
    if(x>=0&&x<5)
    {
        cout<<fixed<<setprecision(3)<< -x + 2.5;
    }else{
        if(x>=5&&x<10)
        {
            cout<<fixed<<setprecision(3)<<2-1.5*(x-3)*(x-3);
        }else{
        cout<<fixed<<setprecision(3)<<x/2-1.5;
        }
    }
    return 0;
}

by 2024yejinghong @ 2023-08-21 16:08:51

完整代码