```cpp
#include <bits/stdc++.h>
using namespace std;
int main()
{
int t = 10,c,d,f = 1920;
double a,b;
scanf("%lf %lf",&a,&b);
t += ceil(a / b);
if (t <= 480)
{
int f1 = 480;
c = (f1 - t) / 60;
d = (f1 - t) % 60;
printf("%02d:%02d",c,d);
}
else
{
c = (f - t) / 60;
d = (f - t) % 60;
printf("%02d:%02d",c,d);
}
}
```
by u_s_er_na_me @ 2023-08-06 15:56:10
@[u_s_er_na_me](/user/1056363)
谢谢，
反复观摩过了，又get到了更简便的语法，谢谢
by rqf20071011 @ 2023-08-07 10:35:39