菜鸟60求助

Jason_HJS_ @ 2023-08-09 19:03:24

/*****************************************
备注：
******************************************/
#include<bits/stdc++.h>
using namespace std;
#define int long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
signed main()
{
    int n;
    cin>>n;
    int x,y;
    int a,b;
    cin>>a>>b;
    double ji=b*100.0/a;
//  cout<<ji<<endl;
    for(int i=1;i<=n-1;i++)
    {
        cin>>x>>y;
        double xin=y*100.0/x;
//      cout<<fixed<<setprecision(3)<<xin<<endl;
        if(ji>=xin)
        {
            if(ji-xin<=0.5)
            {
                cout<<"same\n";
//              cout<<ji-xin<<endl; 
            }   
            else if(ji-xin>0.5)
            {
                cout<<"worse\n";
//              cout<<ji-xin<<endl; 
            }
        } 
        else
        {
            if(xin-ji<=0.5)
            {
                cout<<"same\n";
//              cout<<xin-ji<<endl;
            }
            else if(xin-ji>0.5)
            {
                cout<<"better\n";
//              cout<<xin-ji<<endl;
            }
        }
    }
    return 0;
}

by sandwich03 @ 2023-08-09 19:10:57

@HJS 你题目理解错了。应该每组数据都有一个旧的

by sandwich03 @ 2023-08-09 19:12:17

不对，当我没说

by sandwich03 @ 2023-08-09 19:14:17

应该是xy输反了

by sandwich03 @ 2023-08-09 19:15:14

应该是double xin=x*100.0/y;

by sandwich03 @ 2023-08-09 21:18:27

@HJS 你可以当我上面没说，因为我说错了，但你乘了100.0？你确定？代码改后如下：（能AC）

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin>>n;
    double x,y;
    double a,b;
    cin>>a>>b;
    double ji=b/a;
    for(int i=1;i<=n-1;i++)
    {
        cin>>x>>y;
        double xin=y/x;
        if(ji>=xin)
        {
            if(ji-xin<=0.05)
            {
                cout<<"same\n";
            }   
            else if(ji-xin>0.05)
            {
                cout<<"worse\n";
            }
        } 
        else
        {
            if(xin-ji<=0.05)
            {
                cout<<"same\n";
            }
            else if(xin-ji>0.05)
            {
                cout<<"better\n";
            }
        }
    }
    return 0;
}

by sandwich03 @ 2023-08-09 21:19:05

求关注

by Jason_HJS_ @ 2023-08-10 18:48:45

感谢大佬@linzhi123 已通过

给了关注

by Jason_HJS_ @ 2023-08-10 18:49:13

求互关

by sandwich03 @ 2023-08-10 21:44:52

好的 @HJS