EkSulfur @ 2023-08-18 22:56:56
#include <stdio.h>
int yn(int x);
void run(int x, int y);
int total(int x, int y);
int main(void) {
int x, y;
scanf("%d%d", &x, &y);
printf("%d\n", total(x, y));
run(x, y);
return 0;
}
int yn(int x) {
int a;
if (x % 4 == 0) {
if (x % 100 == 0 && x % 1000 != 0)
a = 0;
else
a = 1;
} else
a = 0;
return a;
}
int total (int x, int y) {
int t = 0;
for (int i = x; i <= y; i++) {
if (yn(i) == 1)
t++;
}
return t;
}
void run(int x, int y) {
for (int i = x; i <= y; i++) {
if (yn(i) == 1)
printf("%d ", i);
}
}
by Use_Imagination @ 2023-08-18 23:12:01
@EkSulfur yn函数写成这样:
int a=0;
if (x % 4 == 0&&x%100!=0||x%400==0)
a =!a;
return a;
by OIerWu_829 @ 2023-08-18 23:15:16
#include <bits/stdc++.h>
using namespace std;
int main()
{
int x, y;
cin >> x >> y;
int cnt = 0;
for (int i = x; i <= y; i++)
{
if (i % 400 == 0 || i % 100 != 0 && i % 4 == 0)
{
cnt++;
}
}
cout << cnt << endl;
for (int i = x; i <= y; i++)
{
if (i % 400 == 0 || i % 100 != 0 && i % 4 == 0)
cout << i << " ";
}
return 0;
}
by FurippuWRY @ 2023-08-19 00:45:19
@EkSulfur 可以看看我的
#include<bits/stdc++.h>
using namespace std;
bool r(long long i){
if(i%4==0 && i%100!=0 || i%400==0 && i%3200!=0) return 1;
else return 0;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
long long x,y,a=0;
cin>>x>>y;
for(int i=x;i<=y;++i){
if(r(i)) a++;
}
cout<<a<<endl;
for(int j=x;j<=y;++j){
if(r(j)) cout<<j<<" ";
}
return 0;
}
by EkSulfur @ 2023-08-21 18:42:36
感谢