z___u___y @ 2023-08-24 14:35:03
#include<bits/stdc++.h>
using namespace std;
int n;
int f[99999];
int main(){
cin>>n;
f[1]=1;
f[2]=2;
int gg=0;
for(int i=1;i<=n;i++){
if(i<=2){
}else
{
f[i]=f[i-1]+f[i-2];
}
gg++;
}
cout<<gg;
}
by zhaojianchao @ 2023-08-24 14:38:20
@zuy 要用高精度
by gjc1108 @ 2023-08-24 14:45:11
@Br00k5xx
要高精啊
by BLX32M_10 @ 2023-08-24 14:46:06
@gjc1108 哦, 好像可以pypy()
by zqhbxsgs @ 2023-10-27 22:28:49
@zuy 你不仅没用高精度,而且你这输出也有问题,应该输出f[n]。