各位大神，哪里错了？

wkm010202 @ 2016-12-02 16:36:26

#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    string s;
    int n;
    cin>>n>>s;
    for(int i=0;i<s.size();i++)
    {
        s[i]=n%26+s[i];
         if(s[i]>122) s[i]=s[i]-26;
    }
    cout<<s<<endl;
    return 0;
}

by liuweixi20050805 @ 2016-12-04 18:20:51

我的似乎有点长：

#include<iostream>
#include<cstring>
using namespace std;
string jmm,zmm;
int n;
int main()
{
    cin>>n>>jmm;
    n=n%26;
    zmm=jmm;
    for(int i=0;i<=jmm.size()-1;i++)
    {
        for(int j=1;j<=n;j++)
        {
            if(jmm[i]=='z') jmm[i]='a';
            else jmm[i]=jmm[i]+1;
        }
        zmm[i]=jmm[i];
    }
    cout<<zmm;
    return 0;
}

by KesdiaelKen @ 2016-12-16 20:59:33

简单版：

#include<cstdio>
#include<iostream>
#include<cmath>
#include<string>
#include<cstring>
using namespace std;
int main()
{
    int n;
    string dr;
    int len;
    cin>>n>>dr;
    len=dr.size();
    for(int i=0;i<len;i++)
    {
        int jl=dr[i]-'a';
        jl=(jl+n)%26;
        dr[i]=jl+'a';
    }
    cout<<dr;
    return 0;
}

by 百里亦守约_test @ 2016-12-27 16:19:08

#include<iostream>
#include<cstring>
using namespace std;
string st;
int n,s;
int main()
{
    cin>>n;
    cin>>st;
    for(int i=0;i<=st.size()-1;i++)
    {
        s=(int(st[i])+n-97)%26;
        if(s==0) cout<<"a"; else cout<<char(s+97);
    }
    return 0;
}
差不多的方法。

by MTer @ 2017-01-10 10:24:52

z+25会溢出