Brilliant11001 @ 2023-08-31 16:16:30
不开O2全RE,开了O2就AC了。。。
请各位大佬帮忙看看是为什么,谢谢!
不开O2
开O2
#include <iostream>
#include <cstring>
#include <cstdio>
#include <queue>
#define int long long
using namespace std;
typedef pair<int, int> PII;
const int N = 100010, M = 500010;
int n, m, hp;
int h[N], e[M], w[M], ne[M], idx;
int f[N];
int dist[N];
bool vis[N];
void add(int a, int b, int c) {
e[idx] = b, w[idx] = c, ne[idx] = h[a], h[a] = idx++;
}
bool dij(int limit) {
memset(dist, 0x3f, sizeof dist);
memset(vis, 0, sizeof vis);
if(f[1] > limit) return false;
dist[1] = 0;
priority_queue<PII, vector<PII>, greater<PII> > heap;
heap.push({0, 1});
while(heap.size()) {
PII t = heap.top();
heap.pop();
int ver = t.second, distance = t.first;
if(vis[ver]) continue;
vis[ver] = true;
for(int i = h[ver]; i != -1; i = ne[i]) {
int j = e[i];
if(f[j] > limit) continue;
if(dist[j] > dist[ver] + w[i]) {
dist[j] = dist[ver] + w[i];
heap.push({dist[j], j});
}
}
}
if(dist[n] > hp) return false;
else return true;
}
signed main() {
// freopen("P1462_1.in", "r", stdin);
// freopen("ans.out", "w", stdout);
scanf("%d%d%d", &n, &m, &hp);
memset(h, -1, sizeof h);
int l = 1, r = 0;
for(int i = 1; i <= n; i++) {
scanf("%d", &f[i]);
r = max(r, f[i]);
}
for(int i = 1; i <= m; i++) {
int a, b, w;
scanf("%d%d%d", &a, &b, &w);
add(a, b, w);
add(b, a, w);
}
while(l < r) {
int mid = l + r >> 1;
if(dij(mid)) r = mid;
else l = mid + 1;
}
if(!dij(l)) cout << "AFK" << endl;
else cout << l << endl;
return 0;
}
by _zlh4_Fishrow_ @ 2023-08-31 16:48:35
数组开太大了吧?
by _zlh4_Fishrow_ @ 2023-08-31 16:49:10
N和M可以去一个0试试看
by Brilliant11001 @ 2023-09-02 18:25:58
@_zlh4Fishrow 不行的,还是RE
by _zlh4_Fishrow_ @ 2023-09-02 21:22:19
@Brilliant11001 我看了一下,好像是h数组在add函数中初始化时溢出了
by _zlh4_Fishrow_ @ 2023-09-02 21:22:43
你再改一改
by Brilliant11001 @ 2023-09-03 08:05:56
@_zlh4Fishrow
怎么可能呢?而且我刚试了一下,开到