第7 10 13报错，但我感觉没问题啊

caibi666 @ 2023-09-02 10:24:31

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    int T;
    cin >> T;
    if (T == 1) {
        cout << "I love Luogu!";
    }
    else if (T ==2) {
        cout << 6 << " " << 4;
    }
    else if (T == 3) {
        cout << (14 / 4) << endl << (14 / 4 * 4) << endl << (14 % 4);
    }
    else if (T == 4) {
        cout << 500.0 / 3;
    }
    else if (T == 5) {
        cout << (260 + 220) / (12 + 20);
    }
    else if (T == 6) {
        cout << sqrt(pow(6, 2) + pow(9, 2));
    }
    else if (T == 7) {
        int balance = 100;
        balance += 10;
        cout << balance;
        balance -= 20;
        cout << balance;
        balance = 0;
        cout << balance;
    }
    else if (T == 8) {
        double r = 5; 
        #define PI 3.141593
        cout << 2 * PI * r << endl;
        cout << PI * r * r << endl;
        cout << 4.0 / 3 * PI * pow(r, 3) << endl;
    }
    else if (T == 9) {
        int ans = 1;
        ans = (ans + 1) * 2;
        ans = (ans + 1) * 2;
        ans = (ans + 1) * 2;
        cout << ans;
    }
    else if (T == 10) {
        int n1 = 8, t1 = 30, n2 = 10, t2 = 6;
        int t3 = 10;
        double v = (1.0 * n1 * t1 - n2 * t2) / (t1 = t2);
        double a = n2 * t2 - v * t2;
        double ans = (a + t3 * v) / t3;
        cout << ans;
    }
    else if (T == 11) {
        cout << 100.0 / (8 - 5);
    }
    else if (T == 12) {
        cout << 'M' - 'A' + 1 << endl;
        cout << char('A' + 18 - 1);
    }
    else if (T == 13) {
        int r1 = 4, r2 = 10;
        double v, l;
        v = 4.0 / 3 * PI * (r1 * r1 * r1 + r2 * r2 * r2);
        l = pow(v, 1.0 / 3);
    }
    else if (T == 14) {
        double a = 1, b = -100, c = 2400;
        double delta, ans;
        delta = pow(b, 2) - 4 * a * c;
        ans = (-b + sqrt(delta)) / (2 * a);
        cout << 110 - int(ans + 0.5) << endl;
    }
    return 0;
}

by donnieguo @ 2023-09-02 10:31:58

@caibi666 7没换行

by g0_Og @ 2023-09-02 10:35:26

其实你用开关语句更简单，用if语句容易把==和=搞混 所以用开关更好

#include<iostream>
#include<cmath>
using namespace std;
int ask;
int main(){
    cin>>ask;
    switch(ask){
        case 1:{
            cout<<"I love Luogu!"<<endl;
            break;
        }
        case 2:{
            cout<<2+4<<" "<<10-2-4<<endl;
            break;
        }
        case 3:{
            int a=14/4;
            cout<<a<<endl;
            cout<<a*4<<endl;
            cout<<14-a*4<<endl;
            break;
        }
        case 4:{
            cout<<500.0/3<<endl;
            break;
        }
        case 5:{
            cout<<(260+220)/(12+20)<<endl;
            break;
        }
        case 6:{
            double a=6,b=9;
            double c=sqrt(a*a+b*b);
            cout<<c<<endl;
            break;
        }
        case 7:{
            int a=100;
            a+=10;
            cout<<a<<endl;
            a-=20;
            cout<<a<<endl;
            a=0;
            cout<<a<<endl;
            break;
        }
        case 8:{
            int r=5;
            double pai=3.141593;
            cout<<2*pai*r<<endl;
            cout<<r*r*pai<<endl;
            cout<<4.0/3*pai*r*r*r<<endl;
            break;
        }
        case 9:{
            cout<<(((1+1)*2+1)*2+1)*2<<endl;
            break;
        }
        case 10:{
            cout<<9<<endl;
            break;
        }
        case 11:{
            cout<<100.0/(8-5)<<endl;
            break;
        }
        case 12:{
            cout<<'M'-'A'+1<<endl;
            cout<<char('A'-1+18)<<endl;
            break;
        }
        case 13:{
            int r1=4,r2=10;
            double pi=3.141593;
            double v=4.0/3*pi*r1*r1*r1+4.0/3*pi*r2*r2*r2;
            v=pow(v,1.0/3);
            printf("%.0lf\n",v);
            break;
        }
        case 14:{
            cout<<50<<endl;
            break;
        }
    }
}

by Leojia2010 @ 2023-09-02 10:40:21

@caibi666 第7题答案没换行，第10题改成

double v = (1.0 * n1 * t1 - n2 * t2) / (t1 - t2);

第13题没有输出,加上

cout<<int(l);

by caibi666 @ 2023-09-02 11:26:27

@donnieguo ohhhhhhhhh，多谢。那10和13捏

by caibi666 @ 2023-09-02 11:26:56

@Jzx2010ses 谢谢

by jsdhwdmaxZYJ @ 2023-09-02 14:06:31

@caibi666 double v = (1.0 * n1 * t1 - n2 * t2) / (t1 = t2); 应为(t1-t2);(10)题。 13题没输出。