最后的 30pts 真的就是那么难吗？

bcbgszyzh @ 2023-09-03 16:30:07

//C++
#include<bits/stdc++.h>
using namespace std;
int DayNum[]={-1,31,28,31,30,31,30,31,31,30,31,30,31};
bool p(int x){
    if( x%4==0 && x%100!=0|| x%400==0 ) 
        return true;
    else
        return false;
}
int main(){
    int a,b;
    cin>>a>>b;
    int cnt=0;
    for(int i=a/10000;i<=b/10000;++i) {
        if(p(i))DayNum[2]++;
        int x=(i%10)*10+i/10%10,y=(i/100%10)*10+i/1000;
        if(x>=1&&x<=12){
            if(y>=1&&y<=DayNum[x]){
                cnt++;
                continue;
            }
        }
        if(p(i))DayNum[2]--;
    }
    printf("%d",cnt);
    return 0;
}

by bcbgszyzh @ 2023-09-03 16:30:58

样例全部 \text{\color{green}AC} 。

by rainbow_cat @ 2023-09-03 16:45:15

#include<bits/stdc++.h>
using namespace std;
int da[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
int reint(int x)
{
    int t;
    string s=to_string(x);
    string b(s.rbegin(),s.rend());
    t=stoi(b);
    return t;
}
int main()
{
    int a,b,sty,stm,std,edy,edm,edd,aa,ans=0;
    cin>>a>>b;  
    sty=a/10000; 
    edy=b/10000; 
    for(int i=sty;i<=edy;i++)
    {
        if(i%100!=0&&i%4==0||i%400==0)
        {
            da[2]=29;
        }
        else
        {
            da[2]=28;
        }
        int r=reint(i),z,x;
        int data=i*10000+r;
        z=r%100;
        r/=100;
        x=r;        
        if(x>=1&&x<=12&&z>=1&&z<=da[x]&&data>=a&&data<=b)
        {
            ans++;
        }
    }
    cout<<ans;
    return 0;
}

参考一下我的

by rainbow_cat @ 2023-09-03 16:45:30

@bcbgszyzh