脑残解法

twogoat @ 2016-12-14 16:53:11

#include<iostream>
#include<iomanip>
using namespace std;
int main()
{
    int a,s=1,b,j[10001],h,k=1,bt=0;
    cin>>a;
    if(a<0) 
    {
    a=a*-1;
    cout<<"-";
}
    b=a;
    while(1)
    {
        h=b%10;
        if(b==0) break; 
        b=b/10;
        j[s]=h;
        s++;
    }
    for(int i=1;i<=s-2;i++)
    {
        k=k*10;
    }
    for(int i=1;i<=s-1;i++)
    {
        j[i]=j[i]*k;
        k=k/10;
    }
    for(int i=1;i<=s-1;i++)
    {
        bt=bt+j[i];
    }
    cout<<bt;
}

by BFSBFSBFSBFS @ 2016-12-14 22:43:54

还可以.取位再乘回来...

by Focus_on @ 2016-12-16 07:52:26

看看我的，用字符数组

#include<string>
#include<cstring>
#include<cstdio>
#include<memory.h>
#define For(a) for(int i=a;i<n;i++);
using namespace std;
int main(){
    char ss[20];
    bool flag=0;
    memset(ss,'\0',sizeof(ss));
    gets(ss);
    int n=strlen(ss)-1;
    if(ss[0]=='-'){
        printf("-");
        flag=1;
    }
    int t=n;
    while(ss[t]=='0') t--;
    if(flag==1)
    for(int i=t;i>=1;i--) printf("%c",ss[i]);
    else
    for(int i=t;i>=0;i--) printf("%c",ss[i]);
    return 0;
}

by 双城 @ 2016-12-17 19:00:30

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<algorithm>
using namespace std;
int main()
{
    char s[1000];
    int sum=0;
    gets(s);
    int len=strlen(s);
    for(int i=len-1;i>=0;i--)
    {
        if(s[i]=='0'&&s[i-1]=='0')
        sum++;
        if(s[i]=='0'&&s[i-1]!='0')
        {
            sum++;break;
        }
    }
    if(s[0]=='-')
    {
        cout<<"-";
    for(int i=len-1-sum;i>=1;i--)
        cout<<s[i];
    }
    else{
        for(int i=len-1-sum;i>=0;i--)
        cout<<s[i];
    }
    return 0;
}
好奇怪居然AC了，可是如果输56065的话会少一个数欸

by wudi2016 @ 2016-12-24 20:57:58

#include<bits/stdc++.h>
#include<cstdio>
#include<cmath>
#include<iostream>
#include<cstdlib>
#include<string>
#include<iomanip>
#include<cstring>
#include<ctime>
#include<algorithm>
#include<queue>
using namespace std;
int main(){
    int n;
    scanf("%d",&n);
    bool yes;
    if(n<0){
        yes=1;
        n=-n;
    }
    int ans=0;
    for(int i=n;i>0;i/=10){
        ans=ans*10+i%10;
    }
    if(yes){
        ans=-ans;
    }
    printf("%d\n",ans);
    return 0;
}