_Maverick_ @ 2023-09-30 19:11:05
#include<bits/stdc++.h>
using namespace std;
long long x[4000000],k;
long long n;
int main()
{
cin>>n>>k;
for(int i=0;i<n;i++)
cin>>x[i];
sort(x,x+n);
cout<<x[k];
}
by 137QWQ @ 2023-09-30 19:14:42
n<5000000
数组开小了
by 137QWQ @ 2023-09-30 19:16:15
快排nlogn过不去 得二分O(n)
by WYZ20030051 @ 2023-09-30 19:31:15
@137QWQ 然而快排能过
by WYZ20030051 @ 2023-09-30 19:31:56
@137QWQ 提交记录
by 137QWQ @ 2023-09-30 20:30:37
@WYZ20030051
强
by _Maverick_ @ 2023-10-01 07:40:39
#include<bits/stdc++.h>
using namespace std;
long long x[5000000+10],k;
long long n;
int main()
{
cin>>n>>k;
for(int i=0;i<n;i++)
cin>>x[i];
sort(x,x+n);
cout<<x[k];
}
@137QWQ @WYZ20030051
by _Maverick_ @ 2023-10-01 07:42:12
@137QWQ @WYZ20030051 这样,只得60分,最后两个测试点TLE了
by WYZ20030051 @ 2023-10-01 11:25:47
@myh00198100 我用了快读和printf输出,还开了O2,用排序做需要卡卡常,常数大是过不去的
by WYZ20030051 @ 2023-10-01 11:26:37
@myh00198100
#include<iostream>
#include<cstdio>
#include<cmath>
#include<string>
#include<cstring>
#include<algorithm>
#include<cassert>
#include<stack>
#include<queue>
#include<vector>
#include<map>
#include<cstdlib>
using namespace std;
#define ll long long
#define ull unsigned long long
int read()
{
int now=0,nev=1;
char c=getchar();
while(c<'0' || c>'9')
{
if(c=='-')
nev=-1;
c=getchar();
}
while(c>='0' && c<='9')
{
now=(now<<1)+(now<<3)+(c&15);
c=getchar();
}
return now*nev;
}
const int MAXN=5e6+10;
int n,k;
int a[MAXN];
int main()
{
n=read(),k=read();
for(int i=0;i<n;i++)
a[i]=read();
sort(a,a+n);
printf("%d",a[k]);
return 0;
}
by _Maverick_ @ 2023-10-01 13:19:39
@WYZ20030051 谢谢