Redeption @ 2023-10-02 11:35:59
#include <stdio.h>
int main()
{
int n = 0, i = 0, num = 0,hr;
char ch;
char a[400];
while ((ch = getchar()) != '\n')
{
n++;
a[i++] = ch;
}
hr = n;
for (int j = 2; j < n; j++)
{
for (int p = 0; p < n; p++)
{
ch = getchar();
a[i++] = ch;
}
ch = getchar();
}
for (int p = 0; p < n; p++)
{
ch = getchar();
a[i++] = ch;
}
n = i;
ch = '0';
printf("%d ", hr);
for (int j = 0; j < n; j++)
{
if (a[j] == ch)
{
num++;
}
else
{
printf("%d ", num);
num = 1;
switch (ch)
{
case'1':
ch = '0';
break;
case'0':
ch = '1';
break;
}
}
}
printf("%d", num);
return 0;
}
by MuLinnnnn @ 2023-10-02 11:46:38
如果写C++那么可以将
while ((ch = getchar()) != '\n')
{
n++;
a[i++] = ch;
}
写成
while (cin >> ch)
{
n++;
a[i++] = ch;
}
by MuLinnnnn @ 2023-10-02 11:47:25
哦对,可以写成
while(~scanf("%c", &ch))
?
by MuLinnnnn @ 2023-10-02 11:50:58
好玄学,都爆RE
by Redeption @ 2023-10-05 12:27:24
@Algophitronrhythm_ 感谢回复,现在也不太知道怎么解决:(