AKkkk_TIX @ 2023-10-04 19:26:43

#include <bits/stdc++.h>
using namespace std;
int main(){
    int n,ii,maxnum = 2,minnum = 11;
    double all;
    cin >> n;
    for (int i = 0; i < n; i++){
        cin >> ii;
        if (ii > maxnum){
            maxnum = ii;
            continue;
        }
        if (ii < minnum){
            minnum = ii;
            continue;
        }  
        all += ii;
   }
   n -= 2;
   all /= n;
   cout << fixed << setprecision(2) << all;
   return 0;
}

by PF_anyone @ 2023-10-05 22:02:20

maxnum的初始化应该是最小的，题目数据从0到10，可能会有全部分数小于2的情况发生

by IAKIOIpwp @ 2023-10-18 20:23:59

两个if语句如果直接跳过的话很可能跳过多个而不是两个

by IAKIOIpwp @ 2023-10-18 20:26:26

n减了2而all很可能不是n-2个数的和

by IAKIOIpwp @ 2023-10-18 20:31:29

建议用个sum来记录和，用和减去最大值和最小值再除以n-2

by IAKIOIpwp @ 2023-10-18 20:38:19

代码：

#include <bits/stdc++.h>
using namespace std;
int main(){
    int n,ii,maxnum = 0,minnum = 11,sum = 0;
    double all;
    cin >> n;
    for (int i = 0; i < n; i++){
        cin >> ii;
        if (ii > maxnum){
            maxnum = ii;
        }
        if (ii < minnum){
            minnum = ii;
        } 
        sum += ii;
   }
   sum = sum - minnum - maxnum;
   n -= 2;
   all = (double) sum / n;
   cout << fixed << setprecision(2) << all;
   return 0;
}

AC了