求助大佬，70分！

QianMengxun @ 2023-10-17 20:04:24

#include <iostream>
#include <cstdio>
#include <cmath>
using namespace std;

int c(double x)
{
    if (x == int(x))    return x;
    else    return x+1;
}

int main()
{
    double s,v;
    cin >> s >> v;
    int t = c(s/v*1.0)+10;  //向上取整+倒垃圾 
    int x = 8,y = 0;
    y -= t;
    while (y < 0)
    {
        x--;    //借位 
        y+=60;
    }
    printf("%02d:%02d",x,y);
    return 0;
}

by C_Rong @ 2023-10-17 20:11:20

#include<bits/stdc++.h>

using namespace std;

int s,v;
bool flag;
int ans;
int ans_h;
int ans_min;

int main(){
    cin>>s>>v;
    if(s / v + 10 > 480)flag = true;
    if(!flag){
        if(s % v == 0)ans = 480 - s / v - 10;
        else ans = 480 - s / v - 10 - 1;
        int tmp = ans;
        while(1){
            if(tmp < 60)break;
            tmp -= 60,ans_h ++;
        }
        ans_min = tmp;
        if(ans_h < 10 && ans_min < 10)cout<<0<<ans_h<<":"<<0<<ans_min;
        if(ans_h < 10 && ans_min >= 10)cout<<0<<ans_h<<":"<<ans_min;
        if(ans_h >= 10 && ans_min < 10)cout<<ans_h<<":0"<<ans_min;
        if(ans_h >= 10 && ans_min >= 10)cout<<ans_h<<":"<<ans_min;
        exit(0);
    }
    else {
        if(s % v == 0)ans = s / v + 10;
        else ans = s / v + 10 + 1;
        int tmp = ans;
        tmp -= 480;
        ans_h = 23;
        ans_min = 60;
        while(1){
            if(tmp < 60)break;
            tmp -= 60,ans_h --;
        }
        ans_min = 60 - tmp;
        if(ans_h < 10 && ans_min < 10)cout<<0<<ans_h<<":"<<0<<ans_min;
        if(ans_h < 10 && ans_min >= 10)cout<<0<<ans_h<<":"<<ans_min;
        if(ans_h >= 10 && ans_min < 10)cout<<ans_h<<":0"<<ans_min;
        if(ans_h >= 10 && ans_min >= 10)cout<<ans_h<<":"<<ans_min;
        exit(0);
    }
}

可以这样写

by chenxizhe2 @ 2023-10-17 20:16:22

这是一道偏向数学思维的题，所以 我们可以打表。

by chenxizhe2 @ 2023-10-17 20:19:09

题解可以看看，我推荐第5和第6个，很清晰明了.

by chenxizhe2 @ 2023-10-17 20:20:19

@chenxinrong 您这个复制题解也得复制一个别人看得懂的吧.

by QianMengxun @ 2023-10-17 20:21:57

@chenxizhe2 谢谢！

by QianMengxun @ 2023-10-17 20:22:46

@chenxinrong 谢谢

by chenxizhe2 @ 2023-10-17 20:30:32

@QianMengxun 没事