FYH666666 @ 2023-10-18 17:25:32
#include<stdio.h>
int main(){
double sum1=0,sum2=0,cnt1=0,cnt2=0,z1=0,z2=0;
int n,k;
scanf("%d%d",&n,&k);
for(int i=1;i<=n;i++){
if(i%k==0){
cnt1=cnt1+i;
z1++;
}
else{
cnt2=cnt2+i;
z2++;
}
}
sum1=1.0*cnt1/z1;
sum2=1.0*cnt2/z2;
printf("%.1lf %.1lf",sum1,sum2);
return 0;
}
by ZhongYuLin @ 2023-10-18 17:37:31
不是过了吗……
by FYH666666 @ 2023-10-18 17:44:26
@ZhongYuLin eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee.....................................................
by liyihan110210 @ 2023-11-05 22:28:59
这个不是对的吗?