SZH0603 @ 2023-10-19 22:23:56
#include<stdio.h>
int main()
{
double k;
int i = 1;
double sum = 0;
scanf("%lf",&k);
while(sum<k)
{
sum = sum + 1*1.0/i;
i++;
}
printf("%d",i-1);
return 0;
}
上面这个代码过不了样例,但是可以AC是什么情况?
by bycwxbd @ 2023-10-19 23:22:07
可能,也许,1是个例外?
by penguin_is_cool @ 2023-10-24 17:06:53
sum=1/i就行了
by Angus66 @ 2023-10-29 11:00:21
#include <bits/stdc++.h>
using namespace std;
int main(){
int a=0;
double num=0;
int i=0;
cin>>a;
while(num<a){
i++;
num=num+1.0/i;
}
cout<<i;
return 0;
}