bata22368030 @ 2023-11-06 10:54:10
#include<bits/stdc++.h>
using namespace std;
int num[100], a, b, c,r=0;
int tem;
int flag1, flag2, flag3,flag=0;
int main() {
cin >> a >> b >> c;
for (int i = 1; i <= 9; i++) {
for (int j = 1; j <= 9; j++) {
for (int k = 1; k <= 9; k++) {
if ((i != j) && (j != k) && (k != i)) {
num[r++] = 100 * i + 10 * j + k;
}
}
}
}
for (int i = 0; i < r; i++) {
for (int j = 0; j < r; j++) {
for (int k = 0; k < r; k++) {
flag1 = num[i] /a;
flag2 = num[j] / b;
flag3 = num[k] /c;
if ((flag1 == flag2) &&(flag2== flag3)) {
cout << flag1 << " " << flag2 << " " << flag3 << endl;
flag = 1;
}
}
}
}
if (flag == 0) {
cout << "No!!!";
}
return 0;
}
by hopelessness @ 2023-11-06 11:23:48
@bata22368030 首先你没有去重,其次,你用int/int会向下取整
by BGM114514 @ 2023-11-06 11:27:10
在极限数据下,
by hopelessness @ 2023-11-06 11:29:56
@BGM114514 Ta这不仅仅是TLE的问题啊
by BGM114514 @ 2023-11-06 11:31:12
@hopelessness 那是当然
by hopelessness @ 2023-11-06 11:34:42
@bata22368030 你可以枚举