lirenzehao @ 2023-11-09 19:34:04

#include<bits/stdc++.h>
using namespace std;
double x[5],y[5],sum;
int f(int a){
    return a*a;
}
void init(){
    for(int i=1;i<=3;i++){
        cin>>x[i]>>y[i];
    }
}
void j(){
    for(int i=2;i<=3;i++){
        for(int j=1;j<i;j++){
            sum+=sqrt(f(x[i]-x[j])+f(y[i]-y[j]));
        }
    }
}
int main(){
    init();
    j();
    printf("%.2lf",sum);
} 

by penguin_is_cool @ 2023-11-09 19:58:50

#include <iostream>
#include <cmath>
using namespace std;
int main(){
    double x1,x2,x3,y1,y2,y3,a,b,c;
    double sum=0.0;
    cin>>x1>>y1>>x2>>y2>>x3>>y3;
    a=abs(sqrt(abs(pow(abs(x2-x1),2))+abs(pow(abs(y2-y1),2))));
    b=abs(sqrt(abs(pow(abs(x3-x1),2))+abs(pow(abs(y3-y1),2))));
    c=abs(sqrt(abs(pow(abs(x3-x2),2))+abs(pow(abs(y3-y2),2))));
    sum=sum+a+b+c;
    printf("%.2f",sum);
}

不用函数也行

我其实函数都不会

by penguin_is_cool @ 2023-11-09 19:59:38

@lirenzehao 其实还要绝对值abs

by lirenzehao @ 2023-11-09 20:02:34

@penguin_is_cool 谢谢，问题已解决

by sbno333 @ 2023-11-09 20:07:47

#include<bits/stdc++.h>
using namespace std;
double x[5],y[5],sum;
double f(double a){//不开double建祖宗
    return a*a;
}
void init(){
    for(int i=1;i<=3;i++){
        cin>>x[i]>>y[i];
    }
}
void j(){
    for(int i=2;i<=3;i++){
        for(int j=1;j<i;j++){
            sum+=sqrt(f(x[i]-x[j])+f(y[i]-y[j]));
        }
    }
}
int main(){
    init();
    j();
    printf("%.2lf",sum);
}