ONicklgzh @ 2023-11-09 19:53:01
#include <stdio.h>
int main(){
int n,i;
double eff1,eff2;
double a[50],b[50];
scanf("%d",&n);
scanf("%lf",&a[1],&b[1]);
for(i=2;i<=n;i++){
scanf("%lf %lf\n",&a[i],&b[i]);
eff1=b[1]/a[1];
eff2=b[i]/a[i];
if(eff2-eff1>=0.05){
printf("better");}
else if(eff1-eff2>=0.05){
printf("worse");}
else {
printf("same");}
}
return 0;
}
by penguin_is_cool @ 2023-11-09 19:56:51
@ONicklgzh AC代码:
#include <bits/stdc++.h>
using namespace std;
int main(){
int n,sum=5.0;
cin>>n;
double a[n],b[n];
cin>>a[0]>>b[0];
a[0]=b[0]/a[0]*100.0;
for (int i=1;i<n;i++){
cin>>a[i]>>b[i];
a[i]=b[i]/a[i]*100;
}
for (int i=1;i<n;i++){
if (a[i]>a[0]-5 and a[i]<a[0]-5) cout<<"same\n";
else if (a[i]>a[0]+sum) cout<<"better\n";
else if (a[i]<a[0]-sum) cout<<"worse\n";
else cout<<"same\n";
}
}
by penguin_is_cool @ 2023-11-09 19:57:22
@ONicklgzh 你搞的有一点复杂了
by ONicklgzh @ 2023-11-09 21:14:30
@penguin_is_cool 有没有c语言的解法啊 没学过c++
by penguin_is_cool @ 2023-11-09 22:16:24
@ONicklgzh 哦我只学过c++,但c++其实跟c语言差不多,所以可以试一下。